A more complete example, using some file with lines containing a date string:
for d in {17..27} ; do
N=$(grep 2012_01_$d /tmp/somefile | wc -l)
echo -n "Jan $d: $N "
printf "=%.0s" $(seq $N)
echo
done
N=$(grep 2012_01_$d /tmp/somefile | wc -l)
echo -n "Jan $d: $N "
printf "=%.0s" $(seq $N)
echo
done
Jan 17: 28 ============================
Jan 18: 22 ======================
Jan 19: 43 ===========================================
Jan 20: 32 ================================
Jan 21: 0 =
Jan 22: 0 =
Jan 23: 46 ==============================================
Jan 24: 50 ==================================================
Jan 25: 50 ==================================================
Jan 26: 51 ===================================================
Jan 27: 41 =========================================
If you're doing it for constant numbers, you can use {1..10} instead of $(seq 10), but {1..$N} doesn't seem to work.
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